If the areas of the three adjacent faces of a cuboidal wooden box are 120 sq cm, 72sq cm and 60 sq cm, then find the surface area and volume of the box
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L= 12
B= 10
H= 6
Therfore
volume will
=L × B × H
=12 × 10 × 6
=720cube cm
Therefore surface area
= 2× (lb+bh+hl)
= 2× (12×10+10×6+6×12)
= 2× (120+60+72)
= 2× 252
= 504 sq.cm
B= 10
H= 6
Therfore
volume will
=L × B × H
=12 × 10 × 6
=720cube cm
Therefore surface area
= 2× (lb+bh+hl)
= 2× (12×10+10×6+6×12)
= 2× (120+60+72)
= 2× 252
= 504 sq.cm
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