If the areas of the three adjacent faces of a cuboidal box are 120sq.Cm, 72sq.Cm and 60sq.Cm respectively, find the volume of the box.
Answers
Answered by
5
720sq cm
vol= lbh
l*b=120
b*h=72
h*l=60
lbh=√(120*72*60) = 720
vol= lbh
l*b=120
b*h=72
h*l=60
lbh=√(120*72*60) = 720
Answered by
33
ANSWER :-
GIVEN:-
- Length = l
- Breadth = b
- Height = h
- Area of three adjacent faces of the cuboid are : 120 cm^2 ; 72 cm^2 ; 60 cm^2.
ATQ,
l × b = 120 ...............(1)
l × h = 72 ...................(2)
b × h = 60 ................(3)
Multiplying (1), (2) and (3), we get
(l × b) × (l × h) × (b × h) = 518400.............(4)
And,
Volume of the cuboid = l × b × h
∴ V = l b h
Squaring on both sides, we get
V^2 = l^2 × b^2 × h^2
∴ V^2 = 518400.
Taking square root on both the sides,
we get,
V = 720 cm^3.
WHAT IS A CUBOID?
◇ A cuboid is a three dimensional figure
◇ It has 6 faces and 8 vertices.
◇ It has 12 edges.
◇ Example : Box, book, etc...
◇ It forms a convex polyhedron.
◇ It has a solid composition.
◇ A cuboid is also known as a rectangular prism.
◇ All cubes are cuboids.
◇ All cuboids are not cubes.
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