Question

if the areas of three adjacent faces of a cuboid are 8cm^2 ,18cm^2,25cm^2 then determine the volume of the cuboid

Answer 1

Let its sides be l cm,b cm and h cm.then,
a/q
lb=8cm^2
bh=18cm^2
lh=25cm^2
on multiplying all three.
lb*bh*lh=8*18*25
(lbh)^2=8*18*25
lbh=(8*18*25)^1/2
lbh=60cm^3
hence,volume of cuboid is 60cm^3.

Answer 2

Given:

"Areas of three adjacent faces"of a cuboid are$8 cm^{2}, 18 cm^{2}, 25 cm^{2}$

To find:

"The volume of the cuboid"

Answer:

Given that

Areas of the Cuboid three adjacent faces are $l \times b=8 cm^{2}, b \times h= 18 cm^{2} and h \times l= 25 cm^{2}$

Let assume cuboid volume is V

Product of adjacent faces of cuboid is $lb \times bh \times hl$

$l \times b=8 cm^{2},$

$b \times h=18 cm^{2} and$

$b \times h=25 cm^{2}$

$(lb \times bh \times hl) = V$

$(l \times b \times h)^ {2} = V$

$V^ {2}= l \times b \times h$

$\sqrt {V} = 8 \times 18 \times 25$

$\sqrt {V} = 3600$

$V = 60 cm^{3}$