If the areas of two similar triangles162 and 200 find the ratioof perimeters
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Two triangles are similar if the sides of one triangle are k times larger than the sides of other triangle.
So ratio of areas will be 1:k² (smaller:larger)
i.e 1/k² = 162/200
⇒ k² = 200/162
⇒ k = √(200/162) ~ 1.111
So perimeter ratio is 1:k = 1:1.111 ~ 0.9
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