Math, asked by sudersansuder03, 4 months ago

If the arithmetic mean of 6a and 8b is greater
than 100 and a is four times of b, then the
smallest possible integer value of a is

Answers

Answered by lahari60

11

Answer:

a. m. of given numbers is 6a+8b/2

=3a+4b

3a+4b>100a+4b

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