Question

If the arithmetic mean of numbers 7,11,x,3,y,2 is 11 then the arithmetic mean of x and y is:

Answer 1

Answer:

given,  $\frac{7 + 11 + x + 3 + y + 2}{6}$ = 11

solving,

x + y = 43

arithmetic mean of x + y = (x + y)/2 =  43/2

Answer 2

The Arithmetic mean of X and Y would be 43/2

Given

• arithmetic mean 11
• 7,11,x,3,y,2

To find

• arithmetic mean of x and y

Solution

we are provided with the Arithmetic mean of 6 numbers in which two are variables and are asked you find the Arithmetic mean of the two variables contained in the given numbers.

we know that Arithmetic mean is given by the sum of all numbers divided by the number of numbers included.

therefore,

11 = (7+ 11+ x+ 3+y+ 2)/6

or, 11 = (23 +x + y)/6

or, 11×6 = 24 + x + y

or, 66 -23 = x+y

or, 43 = x+y

now the arithmetic mean of X and Y would be,

(x+y)/2 {there are two variables included so 2 would be divided}

or, (43)/2

or, 43/2

Therefore, the Arithmetic mean of X and Y would be 43/2