If the arithmetic mean of three consecutive numbers is 63, find the second number.
Answers
Answered by
2
Answer:
sorry i dont know
Step-by-step explanation:
kisi aur se puch lo bhai
Answered by
0
Answer:
Let the first no. be (x-1),
second number be x,
third number be (x+1)
Then, arithmetic mean=63
=[(x-1)+x+(x+1)]/3=63
=(x-1+x+x+1)/3=63
=3x/3=63
=x=63
Therefore, first no. =( x-1)=63-1=62
second number=63
third number=(x+1)=63+1=64
Similar questions