If the arithmetic mean of two numbers a and b ,a>b>0 is five times geometric mean then
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Answered by
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From the information we are given:
1/2(a+b)=5√ab
Multiply both sides by 2 to get:
a+b=10√ab
Square both sides to get:
(a+b)2=a2+2ab+b2=100ab
Subtract 4ab from both ends to get:
(a−b)2=a2−2ab+b2=96ab
So:
(a+b/a−b)2=100ab/96ab=25/24=5square⋅6/12square9=(5√612)square
So since a>b we can take the positive square root to find:
a+b/a−b=5√612
Hope u understood
any confusion please fell free to contact me
1/2(a+b)=5√ab
Multiply both sides by 2 to get:
a+b=10√ab
Square both sides to get:
(a+b)2=a2+2ab+b2=100ab
Subtract 4ab from both ends to get:
(a−b)2=a2−2ab+b2=96ab
So:
(a+b/a−b)2=100ab/96ab=25/24=5square⋅6/12square9=(5√612)square
So since a>b we can take the positive square root to find:
a+b/a−b=5√612
Hope u understood
any confusion please fell free to contact me
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