if the arithmetic mean of X, x+3, x+6 and x+12 is 10 find the value of x
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Step-by-step explanation:
Value \:of\: x = 4Valueofx=4
Step-by-step explanation:
\begin{gathered}Given \: observations \:are \:\\x,x+3,x+6,x+9 \: and \: x+12 \: is \: 10 \end{gathered}
Givenobservationsare
x,x+3,x+6,x+9andx+12is10
\boxed {Mean(x)=\frac{Sum\:of\: observations}{Number \: of \: observations}}
Mean(x)=
Numberofobservations
Sumofobservations
Mean=10Mean=10
\implies \frac{x+x+3++x+6+x+9+x+12}{5}=10⟹
5
x+x+3++x+6+x+9+x+12
=10
\implies \frac{5x+30}{5}=10⟹
5
5x+30
=10
\implies \frac{5(x+6)}{5}=10⟹
5
5(x+6)
=10
\implies x+6=10⟹x+6=10
\implies x = 10-6⟹x=10−6
\implies x = 4⟹x=4
Therefore,
Value \:of\: x = 4Valueofx=4
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