Question

if the arrangement in above fig is given a downward acceleration (a) then the ratio of tensions T1 and T2 in string is
A) ( Ma + Mb) / Mb
B) ( Ma + Mb) / Ma
C) Ma - Mb/ Ma + Mb
D) None of the above​

Answer 1

Answer : A) ( Ma + Mb) / Mb

Explanation :

Tension = Total Mass of object × acceleration

so, T1 = (Ma + Mb) × a

T2 = Mb × a

so, T1/T2 = (Ma + Mb) / Mb

Hope it helps.....✌