Question

If the atomic mass of "x" is 16 u, then the
vapour density of its triatomic gas is :-​

Answer 1

Answer:

Molecular mass of oxygen = 32

Vapour density of oxygen =

2

32

=16

Thus, vapour density of the gaseous element =16×5=80

Molecular mass of the gaseous element =80×2=160

As the molecule is triatomic, its atomic mass =

Atomicity

Mol.mass

=

3

160

=53.33

Answer 2

Given: Atomic mass of x is 16u.

To find: Vapour density of its triatomic gas

Solution: Atomic mass of x= 16u

But we know that atomic mass of oxygen (O) is 16u. Therefore, element x is oxygen.

The triatomic gas of oxygen is O3.

Molar mass of O3

= 3 × atomic mass of O

= 3 × 16

= 48 u

The relation between vapour density and molar mass of a compound is given as:

Vapour density = Molar mass / 2

Here, molar mass of O3 = 48 u

Therefore,

Vapour density = 48/2

= 24

The vapour density of triatomic mass of oxygen is 24.