If the average age of doctors and lawyers is 40,if the doctors average age is 35 and lawyers average is 50,find the ratio of the sum of the ages of doctors to the sum of the ages of lawyers.
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let the sum of ages of doctors and lawyers be A and B
and the no. of doctors and lawyers be m and n
then (A+B)/(n+m)=40
A/m=35, B/n=50
A=35m , B=50n
(A+B)/(n+m)=(35m+50n)/(n+m)=40
35m+50n=40n+40m
10n=5m
n=2m
therefore
(sum of ages of doctor)/(sum of ages of lawyers)=(A/B)
A/B=35m/50n=35m/100m=0.35
and the no. of doctors and lawyers be m and n
then (A+B)/(n+m)=40
A/m=35, B/n=50
A=35m , B=50n
(A+B)/(n+m)=(35m+50n)/(n+m)=40
35m+50n=40n+40m
10n=5m
n=2m
therefore
(sum of ages of doctor)/(sum of ages of lawyers)=(A/B)
A/B=35m/50n=35m/100m=0.35
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