If the average (arithmetic mean) of 3a and 4b
is less than 50 and a is twice b, what is the
largest possible integer value of a?
(B) 10
(D) 19
(A) 9
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given a =2b
b=a\2•••••••••1
a×50
and mean of 3 a+4b<50
or3a+4b
putting b=a/2 from 1
3a+2a<
5a<100
a<100
also as a = 2b then is a even
thus largest possible integar number
Thanks ❤️
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