If the average atomic mass of an element having 2 isotopes is 14.0067, the percentage abundance of the isotopes of mass 14 and 15 respectively are: a)99.33 and 0.67 b)74.5 and 25.5 c)30 and 70 d)65 and 35
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Average atomic mass= 14.0067u
Mass of isotope 1 = 14u
Mass of isotope 2 =15u
Percentage=
14.0067=14×(x/100)+15× (100-x)/100
14.0067=14x +1500 -15x/100
cross multiplication of 14.0067 and 100
1400.67= -x+1500
- x= 1400.67-1500
- x= -99.33
x=99.33
Percentage of 1st isotope = 99.33%
Percentage of 2nd isotope = 100-99.33
= 0.67%
so, answer (a) is correct in this question
Mass of isotope 1 = 14u
Mass of isotope 2 =15u
Percentage=
14.0067=14×(x/100)+15× (100-x)/100
14.0067=14x +1500 -15x/100
cross multiplication of 14.0067 and 100
1400.67= -x+1500
- x= 1400.67-1500
- x= -99.33
x=99.33
Percentage of 1st isotope = 99.33%
Percentage of 2nd isotope = 100-99.33
= 0.67%
so, answer (a) is correct in this question
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