Question

if the average force exerted by wind on the car is 1000 n in north east direction what is the work done by that force on the car?

Answer 1

Concept:

• Work done
• Forces
• Expressing work in terms of forces and displacement
• Vectors

Given:

• The magnitude of the force exerted by the wind = 1000N
• The direction of the force exerted by the wind is in the northeast which is 45°

Find:

• The work done by the force of the wind

Solution:

• Work is the scalar product of force and displacement
• W = F.x
• W = F x cos α
• F = 1000N, let displacement be x and the angle α = 45°
• W = 1000x cos 45°

• W = 1000x (1/√2)
• W = 500√2x J

The work done by the force is 500√2x J where x is the displacement.

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Answer 2

Concept:

Work done

Forces

Expressing work in terms of forces and displacement

Vectors

Given:

The magnitude of the force exerted by the wind = $1000N$

The direction of the force exerted by the wind is in the northeast which is $45$°

To Find:

The work done by the force of the wind.

Solution:

Work is the scalar product of force and displacement

$W = FxW = F x cos \alpha$

$F = 1000N$, let displacement be x and the angle $\alpha = 45$°

$W = 1000* cos 45\\W = 1000* (1/\sqrt{2} )\\W = 500\sqrt{2} J$

The work done by the force is$500\sqrt{2} x J$ where $x$ is the displacement.

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