Question

If the average of 5 consecutive even numbers is 10, find the middle number?

Answer 1

Answer:

Please find the attachment

Answer 2

$\dfrac{2n+2n+2+2n+4+2n+6+2n+8}{5}=10$

The middle number is $2n+4$.

$\dfrac{2n+2n+2+2n+4+2n+6+2n+8}{5}=10\\\\2n+2n+2+2n+4+2n+6+2n+8=50\\10n+20=50\\10n=30\\n=3\\\\2n+4=2\cdot3+4=10$

So it's 10.