Question

If the average of 5 consecutive integers is 12, what is the sum of the least and greatest of the 5 integers?

Answer 1

Answer:

Step-by-step explanation:

k , k + 1 , k + 2 , k + 3 , k + 4 and k + 5 are 5 consecutive integers, then

(k + k + 1 + k + 2 + k + 3 + k + 4)/5 = 12

(5k + 10)/5 = 12

k + 2 = 12

k = 10.

k + k +5 = 10 + 15 = 25