Math, asked by vshal6587, 10 months ago

If the average of 5 consecutive numbers in 29 find the smallest number in the series

Answers

Answered by BrainlyPromoter
7

Answer: 63 Step-by-step explanation: Let the consecutive numbers be x, ( x + 1 ), ( x + 2 ), ( x + 3 ) and ( x + 4 ).  We know that average of the numbers is the sum of quantities by number of quantities.  So,  Average of the numbers = ( x + x + 1 + x + 2 + x + 3 + x +4 ) / 5 But, according to the question, Average of the numbers = 29  Therefore,  ( x + x + 1 + x + 2 + x + 3 + x +4 ) / 5 = 29 ( 5x + 10 ) / 5 = 29 5x + 10 = 29 * 5 5x + 10 = 145 5x = 145 - 10 5x = 135 x = 135 / 5 x = 23  Since, the first among the consecutive numbers will be the smallest of all. Smallest Number in the series = First of the series = x Smallest Number = 23

Answered by Anonymous
5

 \huge \bf \pink{   \mathbb{H}ey  \: there !! }


▶ Given :-

→ Average of 5 consecutive numbers = 29 .


▶ To find :-

→ Smallest number in the series .



▶ Solution :-

Let the number [ having difference 1 ] be x, ( x + 1 ), ( x + 2 ), ( x + 3 ), ( x + 4 ).


We know that :-

 \bf  \green {Average =  \frac{Sum \:  of \:  all \:  observations }{ Number \:  of  \: observations .}} \\  \\  =  > 29 =  \frac{(x )+ (x + 1) + (x + 2) +( x + 3) +( x + 4)}{5} . \\  \\  =  > 29 \times 5 = 5x + 10. \\  \\  =  > 145 = 5x + 10. \\  \\  =  > 5x = 145 - 10. \\  \\  =  > 5x = 135. \\  \\  =  > x =  \frac{135}{5} . \\  \\  \huge \blue{ \boxed{ \boxed{ \therefore x = 27.}}}


Here, the smallest number is x .

So, the smallest number in series is 27 .


✔✔ Hence, it is solved ✅✅.




 \huge \orange{ \boxed{ \boxed{ \mathcal{THANKS}}}}



 \huge \bf \red{ \#BeBrainly.}
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