If the average of 99 consecutive odd numbers is 999 .Fimd the sum of the second and the last number
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x+(x+1)+........+x+98 / 99 = 999
99x+4753 = 98901
99x = 94148
X = 951
Hence 2nd no. is x+1=952
Last no. =x+98= 1049
Sum of 2nd and last no. = 2001
x+(x+1)+........+x+98 / 99 = 999
99x+4753 = 98901
99x = 94148
X = 951
Hence 2nd no. is x+1=952
Last no. =x+98= 1049
Sum of 2nd and last no. = 2001
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