if the average of a,b,c be M and ab +bc = -ca, then average of a²,b²,c² is
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Answer:
3M^2
Step-by-step explanation:
a+b+c/3 = M
or (a + b + c) = 3M
Now, (a + b + c)^2 = (3M)^2 = 9M^2
a^2 + b^2 + c^2 + 2 (ab + bc + ca) = 9M^2
a^2 + b^2 + c^2 = 9M^2
(ab + bc + ca) = 0]
∴ Average = 9M^2/3 = 3M^2
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