Question

If the average of five consecutive integers is 21, find the biggest integer.​

Answer 1

Answer:

Divide the sum of the integers by the number of integers. In our example, the sum of the integers is 24, and there are five integers total, so this is the formula: 24 / 5 = 4.8. For the set of integers 4, 5, 7, 2 and 6, the average is 4.8.

Step-by-step explanation:

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Answer 2

Answer:

Let the 5 consecutive numbers be denoted as x,x+1,x+2,x+3, and x+4 , respectively.

It is given that their average is 13 .

Therefore,

(x+(x+1)+(x+2)+(x+3)+(x+4))/5=13

Simplifying the fraction gives

(5x+10)/5=13

5x+10=65

5x+10−10=65−10

5x=55

x=55/5

x=11

Therefore, the five consecutive numbers are 11,12,13,14 and 15 .

Now, to answer the question, the average of the first four consecutive numbers is

(11+12+13+14)/4=12.5

The answer is 12.5

Step-by-step explanation:

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