Question

if the average of five consecutive number is 48 then find the product of the least and the greatest number​

Answer 1

Answer:

Answer is 2300.

Step-by-step explanation:

Let the 5 consecutive numbers be x , x+1 , x+2 , x+3 , x+4

Given, average =48

(x +x+1 +x+2+x+3+x+4)

Their average = ---------------------------

5

5x+10

48 = --------------

5

(48*5) = 5x +10

240= 5x +10

240 -10 =5x

230 =5x

x=230 / 5

Therefore x = 46.

So the consecutive nos are 46,47,48,49,50.

So the greatest number is 50

the smallest number is 46

Their product is (50*46)= 2300(Ans).

Answer 2

⇒ Given:

The average of 5 consecutive numbers is 48.

⇒ To Find:

The product of the least and the greatest number.

⇒ Analysis:

The first thing we will be doing in this question is providing an expression for each number. After putting the values in the formula to find the mean, we will all the required numbers. From this, we will find the least and the greatest number and their product.

⇒ Formula to be used:

→ $\boxed{\sf{Mean=\dfrac{Sum\:of\:all\:values}{No.\:of\:values}}}$

⇒ Solution:

Let the least number be a.

The other four numbers will be:

a + 1 , a + 2, a + 3, a + 4

The no. of values is 5.

We know that the mean of these numbers is 48.

Forming an equation:

$\sf{48=\dfrac{a+a+1+a+2+a+3+a+4}{5}}$

$\sf{=48=\dfrac{5a+10}{5}}$

$\sf{=48\times5=5a+10}$

$\sf{240=5a+10}$

$\sf{240-10=5a}$

$\sf{230=5a}$

$\sf{\dfrac{230}{5}=a}$

$\sf{a=46}$

So,

a + 1 = 47

a + 2 = 48

a + 3 = 49

a + 4 = 50

Least number = 46

Greatest number = 50

Product =46 x 50

= 2300

Hence the product is 2300.