If the average of five consecutive whole numbers is 18 what is the smallest number
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Step-by-step explanation:
let the smallest number be x
five consecutive numbers are: x, x+1, x+2, x+3, x+4
average= sum of observation/no. of observation
average=18
(x)+(x+1)+(x+2)+(x+3)+(x+4)/5=18
5x+10/5=18
5(x+2)/5=18
x+2=18
x=18-2
x=16
smallest number is 16
and consecutive numbers are
16,17,18,19,20
Answered by
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Answer:
The average of any five consecutive oddnumbers is the third number of the sequence (in this case, c). You can prove this by setting a equal to c-4, b = c-2, d= c+2, and e= c+4. Add those four numbers together with c, and the sum of the five numbers is 5c.
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