Question

If the average of m numbers is n^2 and the average of n numbers is m^2 then the average of (m+n) numbers will be?

Answer 1

Answer:

Step-by-step explanation:

Sum of m number is equal to mn^2

Sum of a number is equal to nm^2

Then avg of m+n = mn^2+nm^2/m+n

mn(m+n)/m+n

Avg. = mn