Question

If the average of seven consecutive even
numbers is 62, then the one fourth of twice of total of first and sixth number is? ​

Answer 1

let the first of the given 7 numbers be 'm'

Then, the numbers are:

m,m+2,m+4,m+6,m+8,m+10,m+12

BTP,

(m+m+2+m+4+m+6+m+8+m+10+m+12)/7=62

or,(7m+42)/7=62

or,7(m+6)/7=62

or,m+6=62

or,m=62-6

therefore,

m=56

sixth number = m+10

= 56+10

= 66

THEN

1/4 *2(56+66)

= 1/2*122

= 61

sixth number=