If the average of the first seven consecutive positive integers is "a" and that of the first nine consecutive positive integers is "b". Then what be the value of the square-root of the squared difference of "a" and "b"?
a. 4
b. 2
c. 3
d. 5
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1
Answer:
A
Step-by-step explanation:
If a, b, c, d and e are five consecutive positive integers. What is the unit's digit of ?
Let the numbers are
a , a + 1(b), a + 2(c), a + 3(d), a + 4(e). =
So, basically a = ?
(1) c = 5
Since a + 2 = 5
a = 3.
SUFFICIENT.
(2) a + b is six less than e + d.
a + b = e + d - 6
Here it's clear that under given condition any value of a, b, e and d would satisfy the equation.
INSUFFICIENT.
Answer A.
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