if the average of x, y and 9 is 12, what is the average of x+2, y-6 and 10?
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Step-by-step explanation:
(x+y+9)/3=12
x+y=(12×3) -9
x+y=27 _(equation 1)
now,
=(x+2+y-6+10)/3
= (x+y+6)/3 _[ from equation 1 (x+y=27)]
=27+6/3
=33/3
=11
therefore, the average of x+2,y-6 and 10 is 11
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