Question

If the average velocity of freely falling body is 7m/s. Then find the height at which it is released.

Answer 1

U=0
V=7m/s
A=9.8m/s^2
T=?
U=V+AT
0=7+9.8T
9.8T=-7
T=-7/9.8=1/1.4=10/14=5/7=.71s
Now
S=UT+1/2AT^2
S=0+1/2×9.8×.71^2
S=4.9×7.1×7.1=247.009m(ANSWER)

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