If the avrage of four consecutive even number is 41 . Find the smallest even number
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Answer:
38
Step-by-step explanation:
let the numbers are x, x+2, x+4, x+6
average of four numbers = 41
[x+(x+2)+(x+4)+(x+6)]/4 = 41
(4x+12)/4 = 41
4x+12 = 164
4x =164-12
4x = 152
x = 152/4
x = 38
the smallest even number is 38
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