Question

If the ax3 + 4x2 + 3x -4 and x3 – 4x + a have the same remainder when divided by ( x – 3 ), find the value of a.

Answer 1

Heya!

Here is yr answer.....


Given,

ax³+4x²+3x-4 and x³-4x+a leaves same remaindet, when divided by (x-3)

a = ???

Now,

(x-3) = 0

x = 3


ax³+4x²+3x-4 = x³-4x+a

a(3)³+4(3)²+3(3)-4 = (3)³+4(3)+a

a(27)+4(9)+9-4 = (27)+12+a

27a+36+9-4 = 39+a

27a+41 = 39+a

27a-a = 39-41

26a = -2

a = -2/26

a = -1/13


Hope it hlpz..