If the axes are translated to the point 3,4 and then rotated through an angle 120 about p. The new co ordinates of the point whose original co ordinates are 1,-1 are
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Answer:
p'[(-2 + 5√3)/2, (-5 - √3)/2]
Step-by-step explanation:
Given,
p(x,y) ----- > (x - h, y - k)
(3,4) ------- > (3 - 1, 4 + 1) = (2,5)
Given, ∅ = 120°.
Now,
x' = x cos∅ + y sin∅
= 2 cos(120) + 5 sin(120)
= 2 * (-1/2) + 5 * √3/2
= -1 + (5√3/2)
= (-2 + 5√3)/2
y' = y cos∅ - x sin∅
= 5 * cos(120) - 2 * sin(120)
= 5 * (-1/2) - 2(√3/2)
= -5/2 - (2√3)/2
= -5/2 - √3
= (-5 - √3)/2
Therefore,
p'[(-2 + 5√3)/2, (-5 - √3)/2]
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