If the balloon has a diameter of 8 inches what is the total amount of helium that the balloon will hold to the nearest tenth
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Answer:
Volume of balloon =
3
4
πr
3
=
3
4
×
7
22
×(10)
3
=4190.47 m
3
Mass of the air displaced =4190.47×1.2=5028.56 kg
No. of moles of helium in the balloon =
RT
PV
=
0.082×300
1×4190.47×10
3
=170344
Mass of helium =4×170.344×10
3
g=681.376 kg
Mass of filled balloon =681.376+100=781.376 kg
Payload = Mass of air displaced − Mass of filled balloon =5028.56−781.376=4247.184 kg.
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