If the barometric pressure (Patm) is 752 Torr and h = 123 mmHg, then what is the pressure of the gas in the bulb? Please express your answer in units of atmospheres.
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Given:
The barometric pressure (Patm) is 752 Torr and h = 123 mmHg,
To find:
What is the pressure of the gas in the bulb? Please express your answer in units of atmospheres.
Solution:
From given, we have,
The barometric pressure (Patm) is 752 Torr and h = 123 mmHg.
Therefore, we have,
h = 123 mmHg
we have, 1 mmHg = 1 torr
∴ h = 123 torr
we use the formula,
Pgas = Patm
= 752 + 123
= 875 torr
we have 1 torr = 0.00131579 atm
∴ 875 torr = 1.15132 atm
Therefore, the pressure of gas in atm is 1.15132 atm
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