IF THE BASE AND HEIGHT OF A TRIANGLE ARE IN THE RATIO 2:3 AND THE AREA OF THE TRIANGLE IS 108M^2 FIND ITS BASE AND HEIGHT
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Answer:
12 m and 18 m
Step-by-step explanation:
Let the ratio be 2x : 3x.
Area of triangle = 1/2 × Base × Height
Given area = 108 m²
=> 108 = 1/2 × 2x × 3x
=> 108 = 3x²
=> 108/3 = x²
=> 36 = x²
=> x = 6
Therefore, Base = 2×6 m = 12 m
Height = 3×6 m = 18 m
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12 m and 18 m is the right answer
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