Math, asked by adarshrnair, 4 months ago

IF THE BASE AND HEIGHT OF A TRIANGLE ARE IN THE RATIO 2:3 AND THE AREA OF THE TRIANGLE IS 108M^2 FIND ITS BASE AND HEIGHT

Answers

Answered by asahilthakur
1

Answer:

12 m and 18 m

Step-by-step explanation:

Let the ratio be 2x : 3x.

Area of triangle = 1/2 × Base × Height

Given area = 108 m²

=> 108 = 1/2 × 2x × 3x

=> 108 = 3x²

=> 108/3 = x²

=> 36 = x²

=> x = 6

Therefore, Base = 2×6 m = 12 m

Height = 3×6 m = 18 m

Answered by nareshsaini77117
0

12 m and 18 m is the right answer

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