Question

if the base and perpendicular of a traingle are 8cm and 6m. respectively find the hypotenuse​

Answer 1

Answer:

$\sqrt{79}$

(haypoteous)^2= base^2+perpendicular^2

Answer 2

10m

Step-by-step explanation:

By Pythagoras theorem, we know that

(H)² = (P)² + (B)²

(H)² = (6)² + (8)²

(H)² = 36 + 64

(H)² = 100

H = √100

H = 10m