if the base angle of an isosceles trapezium is 56 degree what is the measure of the other t
wo angle
Answers
Answered by
0
Answer:
Here is your answer:
Step-by-step explanation:
Let ABCD be the isosceles trapezium, where AC║BD
Let ∠ABD be the base angle = 56°
∠ABD = ∠CDB = 56° ( base angles of isosceles triangles are equal)
Consider AC║BD and AB as transversal
⇒ ∠CAB + ∠ABD = 180° (co- interior angles)
⇒ ∠CAB + 56° = 180°
⇒ ∠CAB = 180° - 56°
= 124°
⇒∠CAB = ∠DCA = 124° (base angles- second pair)
hope this helps you!
Explanation:
Similar questions