Question

If the base angles of an isosceles triangle are 15 degree larger than the vertex angle,what are the angles of the triangle?

Answer 1

Let x be the vertex angle,

Angle of the base= 15+x

As we know Base angles r equal we can conclude, the other angle= 15+x

$x + x + 15 + x + 15 = 180 \\ 3x + 30 = 180 \\ 3x = 180 - 30 \\ 3x = 150 \\ x = \frac{150}{3} \\ x = 50$

Vertex angle= x= 50°

Angles of base= x+15= 50+15 = 65°

So the angles are 50°, 65°,65°.

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