Question

if the base of a angled triangle is 6cm and the hypotenuse is 10cm , find its area​

Answer 1

ANSWER

Let ABC is a right angled triangle at B

Base=BC=6cm

HypotenuseAC=10cm 

Using Pythagoras theorem,

AC2=AB2+BC2AB2=AC2−BC2=102−62=100−36AB=64=8cm

Altitude=AB=8 cm 

Now , Area  of triangle =21×base×altitude

=21×6×8=24cm2

Answer 2

$\huge\red{A}\pink(N)\orange(S) \green{W}\blue{E}\gray{R} \\ 24 {cm}^{2}$