If the base of a parallelogram is twice its height and area is 128m2, find the base and height?
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Answer:
Given,
Base = 2 Height
Let Base be a
So, Base = a
Height = 2a
Formula for area of parallelogram = base x height
128 =a x 2a
128 = 2a^2
128/2 = a^2
64 = a^2
√64 = a
a = 8
Since, Base = a = 8 m
Length = 2a = 2x8 = 16 cm
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