Math, asked by Vasudhachaurasia, 1 month ago

if the base of a parallelogram is (x+4), altide to the base is (x-3) and the area is (x²-4), then actual area equal to (a)30 (b)32 (c)60 (d)40.​

Answers

Answered by 57pranavdmandre
0

Answer:

The actual area of the parallelogram would be 60 unit^2

Step-by-step explanation:

Length of parallel sides of a parallelogram are equal.

So, the sum of length of parallel sides= 2(x+4)

Altitude to the base= (x-3)

Area of parallelogram= 1/2*(sum of parallel sides)*(altitude between parallel sides)

Area of parallelogram= 1/2*2(x+4)*(x-3)

x^2-4= x^2-3x+4x-12

x^2 cancel out each other

-4= x-12

x= 12-4

x=8

So, area of parallelogram= x^2-4= 8^2-4= 60

hope it helps you friend!

Answered by attripriya554
0

Answer:

(x+4) (x-3) = (x^2 -4)

x^2 -3x +4x -12 = x^2 -4

x = -4+12

x = 8

the area of parallelogram is 60

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