if the Base of a parallelogram is(y+8), altitude to the Base is (y-6) and the area is(ysq. - 8) Find the actual area of the parallelogram
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Area of parallelogram = base × height = (y+8)(y-6)
=y sq. +2y -48
Area of parallelogram = y sq. -8
Hence y sq. + 2y - 48 = y sq. -8
2y = 40
y = 20
Area of parallelogram = 20 sq. - 8 = 400 - 8 = 392
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