Question

if the base of a parallelogram measures 7 mt. and its area is 105 mt² then how much is its height​

Answer 1

$area \: of \: parallelogram \: = \: \frac{1}{2} \times b \times h \\ = 105 \: = \: \frac{1}{2} \times 7 \times h \\ = \frac{105 \times 2}{7 \times 1} \\ = \frac{15 \times 2}{1 } \\ = \frac{30}{1} \\ = 30 \: meter$

height = 30 m