If the base of a right angle triangle is 8 cm and hypotenuse is 10 cm find its area
subh14:
0.5×10×8=40
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Answered by
2
Base of right angle triangle = 8cm
Hypotenuse = 10cm
Therefore,
(Perpendicular)²= (h)²-(b)² = (10)²-(8)² = 100-64 = 36 .
Perpendicular = ✓36 = 6cm
Therefore,
Area of right angle triangle = 1/2×b×p = 1/2×8×6 = 24cm²
Hypotenuse = 10cm
Therefore,
(Perpendicular)²= (h)²-(b)² = (10)²-(8)² = 100-64 = 36 .
Perpendicular = ✓36 = 6cm
Therefore,
Area of right angle triangle = 1/2×b×p = 1/2×8×6 = 24cm²
it helped thnx
Answered by
1
Area of triangle= base x height x 1/2
using Pythagoras theorem
a^2 + b^2 = c^2
8^2+b^2=10^2
64+b^2=100
b^2=36
b=root 36
b=6
area = 8 x 6 x 1/2
=24cm^2
Hope this helps you!!!
using Pythagoras theorem
a^2 + b^2 = c^2
8^2+b^2=10^2
64+b^2=100
b^2=36
b=root 36
b=6
area = 8 x 6 x 1/2
=24cm^2
Hope this helps you!!!
yes it did thnx
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