If the base of a right-angled triangle is 6 cm and the hypotenuse is 10 cm, find its area.
Answers
Answered by
3
Step-by-step explanation:
base=6 cm
hypotenuse=10 cm
using Pythagoras theorum
H^2 =h^2 +b^2
10^2 = h^2 + 6^2
100= h^2+36
h^2= 100-36
h^2=64
h = square root of 64
=8 cm
area =1/2*b*h
6*8/2
48/2
=24 cm^2
Answered by
7
Answer: UR REQUIRED ANSWER ;-
base = 6cm , hypotenuse = 10cm , perpendicular = ?
first , find perpendicular of the given triangle
perpendicular = √ (hypotenuse)²- (base)²
perpendicular = √(10)²- (6)²
perpendicular = √100 - 36
perpendicular = √64
perpendicular = 8 cm
now , to find area , area = perpendicular×base / 2
= 8 × 6 / 2
= 48 / 2
= 24 cm²
Step-by-step explanation: hope this will help u mate , need feedback plz
itz akansha ,
the dynamite,
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