Math, asked by arsheenashfiquekhan9, 6 months ago

If the base of a right-angled triangle is 6 cm and the hypotenuse is 10 cm, find its area.

Answers

Answered by Mangun
3

Step-by-step explanation:

base=6 cm

hypotenuse=10 cm

using Pythagoras theorum

H^2 =h^2 +b^2

10^2 = h^2 + 6^2

100= h^2+36

h^2= 100-36

h^2=64

h = square root of 64

=8 cm

area =1/2*b*h

6*8/2

48/2

=24 cm^2

Answered by Anonymous
7

Answer: UR REQUIRED ANSWER ;-

base = 6cm , hypotenuse = 10cm , perpendicular = ?

first , find perpendicular of the given triangle

perpendicular = √ (hypotenuse)²- (base)²

perpendicular = √(10)²- (6)²

perpendicular = √100 - 36

perpendicular = √64

perpendicular = 8 cm

now , to find area , area = perpendicular×base / 2

= 8 × 6 / 2

= 48 / 2

= 24 cm²

Step-by-step explanation: hope this will help u mate , need feedback plz

itz akansha ,

the dynamite,

Similar questions