Question

If the base of a right angled triangle is 8 cm and the hypotenuse is 17 cm, find its area
a) 70 sq. cm
b) 110 sq. cm
c) 60 sq. cm​

Answer 1

Answer:

height=v17^2-8^2 =v 25x9=5x3=15

Area = 1/2 basex height

= 8x15/2=60cm2. (c)

Answer 2

Answer:

Option c)

60 sq. cm

The area of the triangle is 60 sq.cm.

Step-by-step explanation:

Given :

Base of the right angled triangle = 8 cm

Hypotenuse = 17 cm

To find :

Its area

Solution :

To get the area, we need to first find its height.

Solving according to the Pythagoras theorem :

Here :

• Base = 8 cm
• Hypotenuse = 17 cm
• Height = ??

Let the height of the triangle be as x

★ (Hypotenuse)² = (Base)² + (Height)²

⇒ (17)² = (8)² + (x)²

⇒ 289 = 64 + x²

⇒ x² = 289 - 64

⇒ x² = 225

⇒ x = $\tt{\sqrt{225}}$

⇒ x = 15

Height = 15 cm

$\rule{300}{1.5}$

As we got the value of the height, find the area.

$\bigstar \: \boxed{\sf{Area = \frac{1}{2} \times Base \times Height }}$

⇒ $\tt{\dfrac{1}{2}}$ × 8 × 15

⇒ 4 × 15

⇒ 60 cm²

$\therefore$ The area of the triangle is 60 sq.cm.