Math, asked by n4278968, 9 months ago

If the base of a right angled triangle is 8 cm and the hypotenuse is 17 cm, find it's area​

Answers

Answered by jyotirmay77
0

Answer:

60cm^2

Step-by-step explanation:

Let the height be x

x^2=17^2-8^2

x^2=289-64

x^2=225

x=15

Area= Half X Base X altitude

Area= 1/2 X (8x15)

= 60cm^2

Answered by venkateshpatil42
18

Answer:

now. .. as u said it is right angle triangle. then.

.... as per pythogorous therom.

if triangle is ABC and B is 90 degree. than ( Ac)^2 = (AB)^2 + (BC)^2

then u will get.

Step-by-step explanation:

17 * 17 = 8*8 + (BC )^2

then 225 =( BC)^2.

then BC = 15. cm

then.

area of the triangle is = 1/2 * base * height

= 1/2 * 8* 15

= 60 cm^2

I hope it helps you mate .

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