if the base of a right triangle is 8cm and area is 24 sq cm its hypotenuse will be
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Area = 24cm²
Base = 8cm
Let its height be h
ATP
½×b×h = 24
=) ½×8×h = 24
=) 4h = 24
=) h = 24/4
=) h = 6
To find hypotenuse (By Pythagoras theorem)
H² = P²+B²
=) H² = (6)²+(8)²
=) H² = 36+64
=) H² = 100
=) H = √100
= 10
ANS:- The hypotenuse is 10.
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