if the base of an isosceles triangle is 6 cm and its perimeter is 16 cm find its area
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4
6cm2
steps
base is 6cm so if a median is imagined then it will be divided into 3 CM
now the perimeter is 16 and the triangle is isosceles so the remaining two sides would be equal so they will be divided into 5 and 5 centimetre now by Pythagoras theorem 5 Sai square minus 3 square that is root of 25 - 9 which is four and formula for area of triangle is half of base into height the product of base into height is 12 so it's half would be 6 centimetre square that's the area
steps
base is 6cm so if a median is imagined then it will be divided into 3 CM
now the perimeter is 16 and the triangle is isosceles so the remaining two sides would be equal so they will be divided into 5 and 5 centimetre now by Pythagoras theorem 5 Sai square minus 3 square that is root of 25 - 9 which is four and formula for area of triangle is half of base into height the product of base into height is 12 so it's half would be 6 centimetre square that's the area
BrainlyHulk:
wrong
Answered by
26
HI FRIEND ✋✋
BASE = 6CM
ONE SIDE OF THE TRIANGLE = X
PERIMETER = 16 CM
2X + 6 = 16
X = 5 CM
AREA BY HERONS FORMULA
S = ( 5 + 5 + 6 )/2
S = 8
AREA = √[ S ( S - A ) ( S - B ) ( S - C) ]
AREA = √ [ 8 ( 8 - 5 ) ( 8 - 5 ) ( 8 - 6 ) ]
AREA = √ [ 8 × 3 × 3 × 2 ]
AREA = √ [ 144 ]
AREA = 12 CM²
HOPE IT HELPS
BASE = 6CM
ONE SIDE OF THE TRIANGLE = X
PERIMETER = 16 CM
2X + 6 = 16
X = 5 CM
AREA BY HERONS FORMULA
S = ( 5 + 5 + 6 )/2
S = 8
AREA = √[ S ( S - A ) ( S - B ) ( S - C) ]
AREA = √ [ 8 ( 8 - 5 ) ( 8 - 5 ) ( 8 - 6 ) ]
AREA = √ [ 8 × 3 × 3 × 2 ]
AREA = √ [ 144 ]
AREA = 12 CM²
HOPE IT HELPS
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