Question

-If the base of an isosceles triangle is of length
2a' and the length of altitude dropped to the
base is 'h' then the distance from the midpoint
of the base to the side of the triangle is​

Answer 1

Step-by-step explanation:

let ABC is an isosceles triangle

let AB = AC = b

BC = 2a

altitude AD = h

BD = DC = a

let E is a point from the mid point of the base BC of the triangle ABC

By Pythagoras theorem in right ∆ ABC

b^2 = h^2 + a^2

b = √(h2 + a2)

In right ∆ EDC,

sin C = p/a

p = a sin C equation(1)

now, sin C = h/√(h2+a2)

so,

p = ah/√(h2 + a2)

Hope u will understand!!!