Question

if the base of an isosceles triangle is produced on both sides, prove that the exterior angles so formed are equal to each other ​

Answer 1

Answer:

[TO PROVE]- Angle ABD = Angle ACE. [PROOF]- In Isosceles ∆ABC--- Angle DBC = Angle BCE =180° . So, (Angle DBC - Angle ABC) = (Angle BCE - Angle ACB) => 180° - Angle ABC = 180° - Angle ACB = > Angle ABD = Angle ACE [•. Angle ABC= Angle ACB] Hence, proved.

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